7(x^2-4y^2)=0

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Solution for 7(x^2-4y^2)=0 equation:


Simplifying
7(x2 + -4y2) = 0
(x2 * 7 + -4y2 * 7) = 0
(7x2 + -28y2) = 0

Solving
7x2 + -28y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '28y2' to each side of the equation.
7x2 + -28y2 + 28y2 = 0 + 28y2

Combine like terms: -28y2 + 28y2 = 0
7x2 + 0 = 0 + 28y2
7x2 = 0 + 28y2
Remove the zero:
7x2 = 28y2

Divide each side by '7'.
x2 = 4y2

Simplifying
x2 = 4y2

Take the square root of each side:
x = {-2y, 2y}

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